ZXTape! 2 Micro Maths - Tape 1LCL G. Ludinski1984English Educational24.00 UndeterminedOriginalrTZXed by Andrew Barker For Karl Brown. 1984 Release, Original in 1981 perhaps only available to Education/Schools0 on 26 Topics0 SUITE 1100(A) Factorisation of Algebratic EquationsLCL110A  ji% LCL110A SPECTRUM LS=12 A$(4,LS)  G LUDINSKI 1981 'S$=" " 6:6: 2:6:S$ %" LCL110A  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " A FN$ K P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 jR$="" o P0 p P=P+1 x 470 }SLOW  Q$;"=";  I$ I$="?"3500 I$ I$="" 220 I$U$="(X-"+E$+")" RV$="("+E$+"+X)" \W$="(-"+E$+"+X)" fA$(1)=T$+U$ pA$(2)=U$+T$ zA$(3)=V$+W$ A$(4)=W$+V$  N=4 L$=A$(1) )M$="as square root of "+(E*E)+" = "+E$ W=-11070. 6Q$=Z$+" 2 X "+G$+"X"+D$ H$="Find by trial and error two numbers which multiply to make the constant and which add up tomake the coefficient of X.Write them in the form (X+E)(X+F) where E and F are these numbers " T$="(X"+E$+")" U$="(X"+F$+")" V$="("+E+"+X)" W$="("+F+"+X)" A$(1)=T$+U$ A$(2)=U$+T$ A$(3)=V$+W$ A$(4)=W$+V$  N=4 L$=A$(1) M$="as "+E+" * "+F+" = "+D$  N$="and "+E+" + "+F+" = "+G$  10808 Y$=Y $Y>0Y$="+"+Y$ . 8 B w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="AC"B$="?"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""ƯI$187I$""I$""I$""3503 BR=BR + (I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 B$13502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: 5 (X+1)(X-1) (X-1)(X+1) (1+X)(-1+X) (-1+X)(1+X) S ctwpRefsgNx K of the constantdbZ Factorise yJ D*E= ConstantF+1G0Y-1D-1QDFactorise 2 X -1HIIt is equal to (X+E)(X-E) where E is the square root of the constantE1T(X+1)U(X-1)V(1+X)W(-1+X)nL (X+1)(X-1) Mas square root of 1 = 1I0B) Simple and Compound InterestLCL110B 0& LCL110B SPECTRUM  G LUDINSKI 1982 'S$=" " 6:6: 2:6:S$ %" LCL110B  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " A FN$ K P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 o P0 p P=P+1 x 500 }SLOW  Q$;"=";  I$ I$="?"3500 I$ I$="" 220 LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220 I (I$-A)X180 220  "Yes, well done" C=C+1  352` :.5,5:.73333,2:T1270  "No,";H$;",try again" T=2  130  "Sorry, the answer = "  &L$ . 8M$ J LN$ ^ cS=(C/P*100d) h"Your score = ";S;"%" r |"Do you want more ? (Y/N)"  R$  .R$"Y"R$"y"R$"n"R$"N"R$""362j R$="N"R$="n"450  T=1  110n  "End of program" H=4535  1000 L$="" M$="" N$=""  X=1 M=(*900+100d) &Y=(*9 +1) 0D=(*90Z+10 ) :W=-W DP$=M NY$=Y XX$=D bW=1Y=2 l"Z$=" Interest on `"+P$+" at "+X$ q"V$=" percent for "+Y$+" years " t'Y=1V$=" percent for 1 year " vA=(M*Y*D/100d) A$=A A=0540 %W=-1Q$="Simple" +Z$+" "+V$ +W=-1H$=" S.I.= (P x T x R)/100) "  L$="`"+A$ /M$="as ("+P$+" x "+Y$+" x "+X$+")/100 = "+A$ W=-1900 F=(M*D/100d) B=((M+F)*D/100d) A=F+B A$=A A=0540 )Q$="Compound"+Z$+" percent for 2 years" CH$="I1=(PxR)/100 I2=((P+I1)xR/100... I=I1+I2+..." 0L$="`"+A$+" as I1 = ("+P$+"x"+X$+")/100 = "+F 0M$="I2 = (("+P$+"+"+F+") x "+X$+")/100 = "+B  N$="I = I1 + I2 ="+A$   w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"="I$"^"I$"/"I$""I$""I$""I$""I$""3503 BR=BR + (I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 319,0;S$;S$;VP+2,0:I$: S ctwpNxmVydP342Y2X28Z Interest on `342 at 28V percent for 2 years aA191Q5Simple Interest on `342 at 28 percent for 2 years H S.I.= (P x T x R)/100) L`191Mas (342 x 2 x 28)/100 = 191Is(0C) Statistics ILCL110C .$0 5110 LCL110C COPYRIGHT (C) G.LUDINSKI 1981 F(4)  D(8) 'G$=" " 6:6: 2:6:G$; %" LCL110C  G.Ludinski 1981 "; (G$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 n o P0 p P=P+1 x 500z }  B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220\ I (I$-A)X1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270 150   )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = " " ,B$=L$:5000: 6 @M$;N$ ^ cSC=(C/P*100H) h"Your score = ";SC;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  "End of program" H=4535 L$="" M$="" N$="" W=-W W=1702/  S=0 &I=14 0F(I)=0 :I DS$="" NJ=18 XD(J)=(*4+1) bS$=S$+(D(J))+"," l S=S+D(J) vK=14 D(J)=KF(K)=F(K)+1 K J S$=S$(15p) Z$="WHERE MARKS ARE " W=-1760>  X=0 %(S/8)=(S/8)7101 #IN=8*(S/8)+8-S D(8)=D(8)+IN S$=S$(14`)+D(8) S=S+IN )Q$="mEAN MARK SCORED "+Z$(15)+S$ 4H$="MEAN = TOTAL MARKS SCORED / NUMBER OF SCORES" A=(S/8) L$=A !M$="AS SUM OF ("+S$+")/8 = "+A  900a  X=0 P$=((*4+1))  A=F(P$) 2Q$="lENGTH OF HISTOGRAM OF MARK "+P$+" "+Z$+S$  1H$="LENGTH IS NUMBER OF SCORES WITH MARK "+P$ ,>L$=A+G$(31)+"AS THERE ARE "+A+" SCORES OF MARK "+P$ -BA=1L$=A+G$(31x)+"AS THERE IS 1 SCORE OF MARK "+P$ .M$="" /I=81-1 4K=14 >&F(K)IK=1M$=M$+" " ?.F(K)IK=2M$=M$+" " @*F(K)IK=3M$=M$+" " B(F(K)IK=4M$=M$+" " HF(K)579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;G$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) #B$;19,0:3502 A19,0;G$;G$;G$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$k,B)=A$(B)-480-7*(A$(B)>579)  4C(A$k)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( P d }A**+G ctwpNs@?N 4S1,3,1,3,4,3,3,4ZWHERE MARKS ARE xP3aQ?lENGTH OF HISTOGRAM OF MARK 3 WHERE MARKS ARE 1,3,1,3,4,3,3,4H(LENGTH IS NUMBER OF SCORES WITH MARK 3L?4 AS THERE ARE 4 SCORES OF MARK 3M@         1 2 3 43hS}IB?4 AS THERE ARE 4 SCORES OF MARK 307D) Trigonometry (Problems using Sin, Cos and Tan rules)LCL110D  "  POPULAR 110D COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$ $" LCL110D  G.Ludinski 1981 " (S$:6:0:6 2 <"What is your name?" FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 o P0 p P=P+1 x 500  F10 ;"A":I=14::I:10 ;"B";20;"C": pST=8*23689\+40(:96`,ST-6:0,-40(:568,0:-568,40( Q$;"="; I$ I$="?"3500 I$ I$=""220 LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220 I (I$-A)X180 220  "Yes well done" C=C+1  352` :.5,5:.73333,2:T1270 150: "No,";H$;",try again" T=2  130  "Sorry,the answer = " " ,L$ 6 @M$ J TN$ ^ cSC=(C/P*100d) h"Your score = ";SC;" percent" r |"Do you want more ? (Y/N)" R$ .R$"Y"R$"y"R$"n"R$"N"R$""362j R$="N"R$="n"450  T=1  110n  "End of program" H=4535 L$="" M$="" N$="" B=(*40(+10 ) &J=(*90Z+10 ) 0G=(*70F+10 ) :W=(*3) DK=57.2957795e. N G$=" cm. " X F$=" and " bD$=" degrees " l X=1 vB$=B J$=J C$=G ,Y$="Triangle ABC has a right-angle at B." Z$="AB = "+B$+G$ V$="BC = "+J$+G$ W$="AC = "+J+G$ X$="angle C = "+G+D$ W0770 !Q$=Y$+"Find AC where "+Z$+F$+X$ 3H$="sin (C) = Opposite (AB) / Hypotenuse (AC)" A=(B/(G/K)) A$=A  L$=A$+G$ (M$="as "+B$+" / sin ("+C$+") = "+A$+G$  990 W1830> !Q$=Y$+"Find BC where "+X$+F$+W$  4H$="cos (C) = Adjacent (BC) / Hypotenuse (AC) " A=(J*(G/K))  L$=A+G$ **M$="as "+J$+" x cos( "+C$+" ) = "+ A+G$ 4W=1990 >&Q$=Y$+"Find angle C where "+Z$+F$+V$ H4H$="tan (C) = Opposite (AB) / Adjacent (BC)" RA= ( (B/J)*K) \ L$= A+D$ f M$="as tan (C) = "+B$+" / "+J$ pN$="So angle C = "+A+D$   w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR + (I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: S ctwpNb"jag9ke.G cm. F and D degrees xB34J97C57Y%Triangle ABC has a right-angle at B.Z AB = 34 cm. V BC = 97 cm. W AC = 97 cm. Xangle C = 57 degrees QYTriangle ABC has a right-angle at B.Find AC where AB = 34 cm. and angle C = 57 degrees H,sin (C) = Opposite (AB) / Hypotenuse (AC)a(A40L40 cm. Mas 34 / sin (57) = 40 cm. I0 SUITE 1200A) Differentiation (Calculus)LCL120A ?/4"A 5110 LCL120A COPYRIGHT (C) G.LUDINSKI 1981 LS=7` A$(6@,LS) 6:6: 'S$=" " 2:6:S$; %" LCL120A  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 n o P0 p P=P+1 x 500z }  B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ LI=I$ LIA$(1)="2X+"+E$ HA$(2)="X2+"+E$ RA$(3@)=E$+"+2X" \A$(4)=E$+"+X2" f N=4 p2L$=A$(1)+"AS THE DERIVATIVE OF x^2 IS 2x" z'M$="THE DERIVATIVE OF "+E$+"x IS "+E$ +N$="AND THE DERIVATIVE OF "+G$+" IS ZERO"   w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR + (I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(D$k,B)=D$(B)-480-7*(D$(B)>579)  4C(D$k)=16*A(D$,1)+A(D$,2) 0D$:D$"**"D,C(D$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( d }D**`/32X^3 X^3 32 X^3.32 32X**3 X**3 32X**3.32S ctwp befgZ dIFFERENTIATE WITH RESPECT TO x E8F4G4Y=THE DERIVATIVE OF Ax^N IS NA x^(N-1) Q$dIFFERENTIATE WITH RESPECT TO x 8x^4H\THE DERIVATIVE OF Ax^N IS NA x^(N-1) WHERE ^ IS TO THE POWER OF T32U3n@L32x^3M AS 8 * 4 = 32N AND 4 - 1 = 3 3hS}IB AND 4 - 1 = 307B) Solution of triangles using sine and cosine formulaeLCL120B % 5110 LCL120B SPECTRUM COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; $" LCL120B  G.Ludinski 1981 " (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 n o P0 p P=P+1 x 500z }  ]11 ;"A"::9 ;"c";17;"b":::9 ;"B";15;"a";20;"C": tST=8*23689\+24:96`,ST+8:-16,-32 :80P,0:-64@,32 B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220\ I (I$-A)X1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270 150: "No,";H$;",try again" T=2  130  "Sorry,the answer = " " ,B$=L$:5000: 6 @B$=M$:5000: J TB$=N$:5000: ^ cS=(C/P*100H) h"Your score = ";S;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  "End of program" H=4535 L$="" M$="" N$=""  X=1  B=32 &CT=110/630 0E=(*904+10 ) :F=(*904+10 ) DG=(*70 +10 ) NJ=(*70 +10 ) XE$=E bF$=F lG$=G vJ$=J %Z$="iN TRIANGLE abc, IF ANGLE c = "  W=1 "(*2)=0W=-1 W=17306 GQ$=Z$+G$+"DEGREES, A = "+E$+" M. AND ANGLE a ="+J$+" DEGREES,THEN C " .H$="a / sin A = b / sin B = c / sin C " A=(E*(G*CT)/(J*CT)) A$=A  L$=A$+" M." 2M$="AS "+E$+" X SIN("+G$+") / SIN("+J$+") = "+A$ W=-1810J <Q$=Z$+G$+"DEGREES ,A = "+E$+" M. AND B = "+F$+" M.THEN C " 0H$="c^2 = a^2 + b^2 - 2ab cos(C)" 3A=((E^2+F^2-(2*E*F*(G*CT)))) A$=A  #L$=A$+" M. AS THE SQUARE ROOT OF"  M$=E$+"^2 + "+F$+"^2" "0N$="- 2 X "+E$+" X "+F$+" X COS("+G$+") = "+A$ * END w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR + (I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$j,B)=A$(B)-480-7*(A$(B)>579)  4C(A$j)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( d }S ctwpxb{efMgMj2E25F77G77J50ZiN TRIANGLE abc, IF ANGLE c = QGiN TRIANGLE abc, IF ANGLE c = 77DEGREES ,A = 25 M. AND B = 77 M.THEN C H)c^2 = a^2 + b^2 - 2ab cos(C)aKA75L75 M. AS THE SQUARE ROOT OFM 25^2 + 77^2N- 2 X 25 X 77 X COS(77) = 755hS}IB- 2 X 25 X 77 X COS(77) = 75s0C) PercentagesLCL120C T W&V 5110 LCL120C COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; %" LCL120C  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 o P0 p P=P+1 x 500z  B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ W=-1I$=A$180 W=-1220 I=1̱I$ ,(I$(I)<"0"I$(I)>"9")I$(I)"."220 I 'X<9 ƽ(I$-A)<1180 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270  )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = " " ,B$=L$:5000: 6 @B$=M$:5000: J TB$=N$:5000: ^ cS=(C/P*100H) h"Your score = ";S;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  "End of program" H=4535 L$="" M$="" N$="" A$="" X=0:A=0  B=32 &W=-W 0F=(*9+1) DG=(*9+1) FI=23 G4(F/I)=(F/I)(G/I)=(G/I)F=F/I:G=G/I:583G HI NJ1=(*19+1) X&F=GF/G=(F/G)G/F=(G/F)560 bF>G650" l E=(F*10000'/G)/100d vJ=J1*5  700/  E=(G*10000'/F)/100d H1=G G=F F=H1 J=J1*2  E$=(E) F$=F G$=G J$=J W=1870Y  X=9 ;J>9Q$=J$+" PERCENT CONVERTED INTO A FRACTION" =J<10 Q$=J$+" PERCENT CONVERTED INTO A FRACTION" H$="P PERCENT IS P/100.iF TOP ANDBOTTOM OF FRACTION ARE EXACTLY DIVISIBLE BY THE SAME NUMBERS THEN DIVIDE BY THESE NUMBERS " HU=100H  I=18  F5=0  F2=0 =J/5 =(J/5 )HU/5 =(HU/5 )F5=1  F5=1J=J/5 "F5=1HU=HU/5 *=J/2=(J/2)HU/2=(HU/2)F2=1 4F2=1J=J/2 6F2=1HU=HU/2 >I HA$=J+"/"+HU RL$=A$ \M$="AS "+J$+"/100 = "+A$ fW=-1930h h X=1 p-Q$=F$+"/"+G$+" EXPRESSED AS A PERCENTAGE " z#H$="P/Q IS (P/Q) X 100 PERCENT " |A=E A$=E$ L$=A$+" PERCENT" %M$="AS ("+F$+"/"+G$+") X 100 = "+E$  END w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 I B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$k,B)=A$(B)-480-7*(A$(B)>579)  4C(A$k)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( d }S ctwpxaQbfg@eQ녨jH6hS}sRNE66.66F2G3J16Q2/3 EXPRESSED AS A PERCENTAGE HP/Q IS (P/Q) X 100 PERCENT A66.66L 66.66 PERCENTMAS (2/3) X 100 = 66.66IB0D) Changing bases of numbersLCL120D }u- 5110 LCL120D COPYRIGHT (C) G.LUDINSKI 1981 U(6@) Q(6@) 'S$=" " 6:6: 2:6:S$; %" LCL120D  G.Ludinski 1981 "; (S$:6:0 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 n o P0 p P=P+1 x 500z }  B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220\ I (I$-A)X1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270  )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = " " ,B$=L$:5000: 6 @B$=M$:5000: J TB$=N$:5000: WW=-1300 XW=-1 YW=-1L$+S$ ZW=-1M$+S$ [W=-1N$+S$ \aW=-1O$(64@);:3:O$(65A333M);:5:O$(334N);:0 ^ cS=(C/P*100H) h"Your score = ";S;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  H=4535 L$="" M$="" N$=""  X=0  B=32 &W=-W 0%Z$="tHE DECIMAL EQUIVALENT OF THE " :W=1790E D L1=2 N 970r XE3=EL b 970r lE2=EL v 970r E1=EL  970r E0=EL  990w -F=E0+(E1*2)+(E2*4)+(E3*8) F$=F 9Q$="tHE BINARY EQUIVALENT OF THE DECIMAL NUMBER "+F$ ưH$="TO FIND THE BINARY EQUIVALENTREPEATEDLY DIVIDE BY 2 AND THE BINARY NUMBER IS MADE UP OF THE FINAL RESULT FOLLOWED BY THE REMAINDERS.(R STANDS FOR REMAINDER)" A=E$ A$=E$ 5L$=A$+" AS "+F$+" / 2 = "+((F/2))+" R "+E0 CM$=" "+((F/2))+" / 2 = "+((F/4))+" R "+E1 G$=" " 7N$=" "+((F/4))+" / 2 = "+E3+" R "+E2 (F/4)=0M$="" (F/8)=0N$="" HO$=" Decimal = Binary Tens 1=Eights Fours Twos 1" I=92-1 CF-10 *(F/10 )IO$=O$+S$(11 )+""+S$(20) &F-10 *(F/10 ) 970r HE2=EL R 970r \E1=EL f 970r pE0=EL z 990w Q$=Z$+" OCTAL NUMBER "+E$ UH$="THE OCTAL NUMBER ABCD = (D X 1) + (C X 8) + (B X 8 X 8) + (A X 8 X 8 X 8)" 0A=E0+(E1*8)+(E2*64)+(E3*512) A$=A  L$=A$+" AS" HM$="("+E0+" X 1) + ("+E1+" X 8) + ("+E2+" X 64) + ("+E3+" X 512)"  N$="= "+A$  EL=(*L1)  E$=E3+E2+E1+E0   w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$Qo,B)=A$(B)-480-7*(A$(B)>579)  4C(A$Qo)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( d }!0 @!S ctwpxbZtHE DECIMAL EQUIVALENT OF THE E0001fF1Q0tHE BINARY EQUIVALENT OF THE DECIMAL NUMBER 1HTO FIND THE BINARY EQUIVALENTREPEATEDLY DIVIDE BY 2 AND THE BINARY NUMBER IS MADE UP OF THE FINAL RESULT FOLLOWED BY THE REMAINDERS.(R STANDS FOR REMAINDER)aA0001L0001 AS 1 / 2 = 0 R 1G MNO` Decimal = Binary Tens 1=Eights Fours Twos 1 0 0 0 0 1hS}IBsa0 SUITE 1300A) Indicies in Algebra ILCL130A f  I$h  5110 LCL130A COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; %" LCL130A  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 i P=0 j T=1 l W=1 n o P0 p P=P+1 x 500z }  B$=Q$:5000 I$ I$="?"3500 I$: I$=""220\ LI=I$ I=1LI I$(I)<"0"I$(I)>"9"220\ I (I$-A)X1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270  )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = " " ,B$=L$:5000: 6 @B$=M$:5000: J TB$=N$:5000: ^ cS=(C/P*100H) h"Your score = ";S;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  "End of program" H=4535 M$="" N$=""  X=0  B=32 &E=(*904+10 ) 0F=(*8+2) :G=(*8+2) DG$=G NE$=E XF$=F bW=(*3@) lW0690 vQ$="A^"+G$+" X A^"+F$+" = A^" 5H$="TO MULTIPLY THOSE TYPE OF TERMS,ADD INDICES" A=G+F A$=A  L$="A^"+A$ M$="AS "+G$+" + "+F$+" = "+A$ W1760> #Q$="(A^"+E$+") / (A^"+F$+") = A^" IH$="TO DIVIDE THOSE TYPE OF TERMSSUBTRACT BOTTOM INDEX FROM TOP INDEX" A=E-F A$=A  L$="A^"+A$ M$="AS "+E$+" - "+F$+" = "+A$ W2830O Q$="(A^"+F$+")^"+G$+" = A^"  H$="MULTIPLY INDICES" A=F*G  A$=A * L$="A^"+A$ 4M$="AS "+F$+" X "+G$+" = "+A$ > END w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$Xi,B)=A$(B)-480-7*(A$(B)>579)  4C(A$Xi)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( P d }S cptwxbeHfga4hS}sRNG7E72F2Q (A^2)^7 = A^HMULTIPLY INDICESA14LA^14M AS 2 X 7 = 14IB0Similar TrianglesLCL130B ?+$A 5110 LCL130B COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; %" LCL130B  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 n o P0 p P=P+1 x 500z zST=25-23689\:VG=8*(24-ST):ST+3,20;"P":ST+8,18;"Q":ST+8,26;"R" |DST,7;"A":ST+8,3;"B":ST+8,16;"C" ~d160,8*(17-ST)+4:-14,-24:64@,0:-502,24 [568,8*(20-ST):-24,-44,:96`,0:-72H,44,  23692\,255 B$=Q$:5000:"="; 23658j\,8 I$ I$="?"3500 I$ I$=""220\ X=9172, LI=I$ I=1LI ,I$(I)"-"(I$(I)<"0"I$(I)>"9")220\ I (I$-A)X1804 220\ I$=A$I$=C$1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1264 150   )"No,";:B$=H$:5000:",try again" T=2  122z  "Sorry,the answer = "  ,B$=L$:5000: . @B$=M$:5000: J T W=1B$=N$:5000: ^ W=1 cSC=(C/P*100H) h"Your score = ";SC;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  H=4535 L$="" M$="" N$=""  B=32   X=1 &LA=(*9+1) 0LB=(*9+1) :E=(*9+1) DV$=LA NW$=LB XE$=E bW=-W l Z$="iN TRIANGLES abc AND pqr," v%X$=".aRE THESE TRIANGLES SIMILAR? " W=1860W Y=(*5 ) UY=0B$=Z$+"bc = 4 X qr, ANGLE abc = ANGLE pqr, AND ANGLE acb = ANGLE pqr"+X$ EY=1B$=Z$+"ab = 5 X pq, bc = 5 X qr AND ANGLES acb = prq"+X$ @Y=2B$=Z$+"ab = 3 X pq, bc = 3 X qr AND ac = 3 X pr"+X$ AY=3B$=Z$+"ANGLES abc = pqr, acb = prq AND bac = qpr"+X$ EY=4B$=Z$+"ab = 5 X pq, bc = 5 X qr AND ANGLES abc = pqr"+X$  1210@ Q$=B$ H$="TRIANGLES ARE SIMILAR IF : 1 cORRESPONDING SIDES ARE PROPORTONAL 2 cORRESPONDING ANGLES ARE EQUAL3 tWO CORRESPONDING SIDES ARE PROPORTIONAL WITH THE ANGLE BETWEEN THEM EQUAL"  X=9 Y1790E A$="Y"  C$="YES"  T$="YES)"  810J A$="N"  C$="NO"  T$="NO)" *Y>1L$="y (I.E. "+T$ ,Y1L$="n (I.E. "+T$ 41Y>1M$="sEE RULE "+(Y-1)+" ABOVE" >RY=0M$="AS THIS IS NOT ONE OF THE CONDITIONS FOR SIMILAR TRIANGLES" HPY=1M$="AS THE EQUAL ANGLE MUST BE BETWEEN THE PROPORTIONAL SIDES" \W=-1980u f X=1 pB$="iF TRIANGLES abc AND pqr ARE SIMILAR, pq = "+V$+" FOOT, qr = "+W$+" FOOT, ab = "+(E*LA)+" FOOT AND ANGLES abc = pqr AND bac = qpr THEN bc " z 1210@ Q$=B$ H$="FIND THE RATIO BETWEEN THE TWO CORRESPONDING SIDES WHOSE VALUES ARE GIVEN. tHEN MULTIPLY THE REMAINING SIDE WHOSE VALUE IS GIVEN BY THIS NUMBER " A=E*LB A$=A L$=A$+" FOOT" -M$="AS ab/pq = "+E$+" SO bc/qr IS ALSO "+E$ 3N$="AS qr = "+W$+" SO bc = "+W$+" X "+E$+" = "+A$  LF=B$ LFB1350( I=1̺(LF/B) EL=B*I B$(EL)=" "1340'  B$(EL+1)" "1290!@ B$=B$(EL)+B$(EL+2) LF=LF-1  1340'  K=131x B$(EL-K)" "1335& 'B$=B$(EL-K)+S$(K)+B$(EL-K+1) ( LF=LF+K 2 1340' 7K <I F P#Z=1̺(Z$/32)+1 `BZ=B*Z aBZ>Z$BZ=Z$ bZ$(B*(Z-1)+1BZ); nZ p Z$Q$+"=" s x w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03502 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$q,B)=A$(B)-480-7*(A$(B)>579)  4C(A$q)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( P d }S ctwp@bxeyfts@@x  x hS}!aRNV8W6E4ZiN TRIANGLES abc AND pqr,X.aRE THESE TRIANGLES SIMILAR? QsiN TRIANGLES abc AND pqr,bc = 4 X qr, ANGLE abc = ANGLE pqr, ANDANGLE acb = ANGLE pqr.aRE THESE TRIANGLES SIMILAR? HTRIANGLES ARE SIMILAR IF : 1 cORRESPONDING SIDES ARE PROPORTONAL 2 cORRESPONDING ANGLES ARE EQUAL3 tWO CORRESPONDING SIDES ARE PROPORTIONAL WITH THE ANGLE BETWEEN THEM EQUALANCNOTNO)L n (I.E. NO)M@AS THIS IS NOT ONE OF THE CONDITIONS FOR SIMILAR TRIANGLESBsiN TRIANGLES abc AND pqr,bc = 4 X qr, ANGLE abc = ANGLE pqr, ANDANGLE acb = ANGLE pqr.aRE THESE TRIANGLES SIMILAR? INO/0#Applications of Pythagoras' TheoremLCL130C b  5110 LCL130C COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; %" LCL130C  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 jR$="" n o P0 p P=P+1 x 500z }  W-1135 a10 ;"A":::10 ;"c";16;"b":::10 ;"B";15;"a";20;"C": {ST=8*23689\+40(:96`,ST-6:0,-32 :568,0:-568,32 :140 F14;"A"::::::11 ;"B";16;"H";20;"C": ST=8*23689\+480:128,ST-6:-28,-40(:568,0:-28,40(:0,-40( B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ X=9172, LI=I$ I=1LI ,I$(I)"-"(I$(I)<"0"I$(I)>"9")220\ I (I$-A)X1804 220\ I$=A$I$=C$1804 220\  "Yes,well done" C=C+1  3520 $.5,5:.73333,2 T1262 150   )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = "  ,B$=L$:5000: . @B$=M$:5000: J TB$=N$:5000: ^ cSC=(C/P*100H) h"Your score = ";SC;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  H=4535 L$="" M$="" N$=""  B=32   X=1 &E=(*4+5 ) 0F=(*4+5 ) :E$=E DF$=F NG=((E*E+F*F)) XG$=G bW=-W lW=17101 vjB$="iF THE SHORTER SIDES OF A RIGHT-ANGLED TRIANGLE ARE "+E$+" CM. AND "+F$+" CM. THEN THE HYPOTENUSE "  1210@ Q$=B$ UH$="B^2 = A^2 + C^2 WHERE B IS THE HYPOTENUSE, AND A AND C ARE THE SHORTER SIDES" A=G L$=G$+" CM." +M$="AS HYPOT. ^2 = "+E$+" ^2 + "+F$+" ^2" LE=((E*E)) LF=((F*F)) ^N$="SO HYPOT.= SQUARE ROOT ("+(E*E)+" + "+(F*F)+")"+S$(B-28`-LE-LF)+" = "+G$ W=-1810J rB$="iF AN ISOSCELES TRIANGLE abc HAS ab AND ac = "+G$+" FOOT AND bc = "+(2*E)+" FOOT THEN THE HEIGHT ah "  1210@ Q$=B$ vH$="THE HEIGHT ah BISECTS bc CREATING TWO RIGHT-ANGLED TRIANGLES ahb AND ahc. ah^2 = ab^2 - bh^2" A=((G^2-E^2)) A$=A  L$=A$+" FOOT" )M$="aS bh = "+(2*E)+" / 2 = "+E$ LG=G$ LE=E$  NN$="ah = SQUARE ROOT ("+G$+"^2 - "+E$+"^2)"+S$(B-28-LG-LE)+" = "+A$ * LF=B$ LFB1350( I=1̺(LF/B) EL=B*I B$(EL)=" "1340'  B$(EL+1)" "1290!@ B$=B$(EL)+B$(EL+2) LF=LF-1  1340'  K=131x B$(EL-K)" "1335& 'B$=B$(EL-K)+S$(K)+B$(EL-K+1) ( LF=LF+K 2 1340' 7K <I F P#Z=1̺(Z$/32)+1 XST=8*23689\+480:128,ST-6:-28,-40(:568,0:-28,40(:0,-40( `BZ=B*Z aBZ>Z$BZ=Z$ bZ$(B*(Z-1)+1BZ); nZ p Z$Q$+"=" s x w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$o,B)=A$(B)-480-7*(A$(B)>579)  4C(A$o)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( P d }A**S ctwpRbxefE7F8g G10.-@x Q_iF THE SHORTER SIDES OF A RIGHT-ANGLED TRIANGLE ARE 7 CM. AND 8 CM. THEN THE HYPOTENUSE HNB^2 = A^2 + C^2 WHERE B IS THE HYPOTENUSE, AND A AND C ARE THE SHORTER SIDESa L10 CM.MAS HYPOT. ^2 = 7 ^2 + 8 ^2N-SO HYPOT.= SQUARE ROOT (49 + 64) = 100hS}IB-SO HYPOT.= SQUARE ROOT (49 + 64) = 10u0D) Profit and LossLCL130D +.V 5110 LCL130D COPYRIGHT (C) G.LUDINSKI 1981 'S$=" " 6:6: 2:6:S$; %" LCL130D  G.Ludinski 1981 "; (S$:6:0:6 2 <"What is your name ? " FN$ P Z"Here are some problems ";N$ d C=0 f T=1 h W=1 i P=0 jR$="" n o P0 p P=P+1 x 500z }  B$=Q$:5000:"="; I$ I$="?"3500 I$ I$=""220\ X=9172, LI=I$ I=1LI ,I$(I)"-"(I$(I)<"0"I$(I)>"9")220\ I (I$-A)X1804 220\ I$=A$I$=C$1804 220\  "Yes,well done" C=C+1  3520 :.5,5:.73333,2:T1270 150   )"No,";:B$=H$:5000:",try again" T=2  130  "Sorry,the answer = "  ,B$=L$:5000: . @B$=M$:5000: J TB$=N$:5000: ^ cSC=(C/P*100H) h"Your score = ";SC;" %" r |"Do you want more? (Y/N)" R$ .R$"Y"R$"N"R$""R$"y"R$"n"362j R$="N"R$="n"450  T=1  110\  H=4535 L$="" M$="" N$=""  B=32   X=1 !W=-W &E=(*9+1) 0F=(*904+10 ) :E$=E DF$=F XW=1690, bB$="iF A SHOPKEEPER BUYS CHOCOLATES FOR "+F$+" PENCE AND SELLS THEM FOR "+(E+F)+" PENCE,HIS PROFIT AS A PERCENTAGE OF HIS COST PRICE " l 1210@ vQ$=B$ uH$="PERCENTAGE PROFIT = ((SELL - COST) / COST) * 100 % WHERE SELL = SELLING PRICE, COST = COST PRICE" A=(E*100H/F) A$=A L$=A$+" PERCENT" 0M$="AS (("+(E+F)+" - "+F$+") / "+F$+") X 100"  N$="= "+A$ W=-1800H V=E*100H V$=V uB$="a DEALER WISHES TO MAKE A PROFIT OF "+F$+" PERCENT.iF THE CAR COST HIM `"+V$+" THEN HIS SELLING PRICE MUST BE "  1210@ Q$=B$ IH$="FIND THE PROFIT IN MONEY TERMS THEN ADD IT TO THE COST PRICE" A=(V+(F*E)) A$=A T$=((F*E))  L$="`"+A$  PM$="AS PROFIT = ("+F$+"/100) X "+V$+S$(B-21(-F$-V$)+" = `"+T$ XN$="SO SELLING PRICE = "+V$+" + "+T$+S$(B-220-V$-T$)+" = `"+A$   LF=B$ LFB1350( I=1̺(LF/B) EL=B*I B$(EL)=" "1340'  B$(EL+1)" "1290!@ B$=B$(EL)+B$(EL+2) LF=LF-1  1340'  K=131x B$(EL-K)" "1335& 'B$=B$(EL-K)+S$(K)+B$(EL-K+1) ( LF=LF+K 2 1340' 7K <I F P#Z=1̺(Z$/32)+1 `BZ=B*Z aBZ>Z$BZ=Z$ bZ$(B*(Z-1)+1BZ); nZ p Z$Q$+"=" s x w VP=22 - 23689\:1;19,0;" Calculator mode ";1;19,0 B$="" #BR=0:B$:B$=""3503 B$="?"B$="AC"3510 I=1̱B$:I$=B$(I):(I$<40(ůI$>579)I$" "I$"^"I$"="I$"/"I$""I$""I$""I$""I$""3503 BR=BR+(I$="(")-(I$=")") I BR03503 B$="?"3530 DB$="AC"20,0;S$;19,0:B$="":3502 "B$(B$)="="B$=B$(̱B$-1) B$=""3502 #B$;19,0:3502 A19,0;S$;S$;S$(10 );VP+2,0:I$: I=0̱B$ I=05025  CB=B$(I) CCB<65A(CB91[CB96`)32006},CB:5020 ACB97aCB122z32006},(CB-32 ):5020 32006},(CB+32 ) H=32000} I  D=32000} ?A(A$l,B)=A$(B)-480-7*(A$(B)>579)  4C(A$l)=16*A(A$,1)+A(A$,2) 0A$:A$"**"D,C(A$):D=D+1:5140 3"3E","02","CD","01","16","3E","00","D7","C9","**" ( d }S ctwpRbxef*E6F42~@`x QiF A SHOPKEEPER BUYS CHOCOLATES FOR 42 PENCE AND SELLS THEM FOR 48 PENCE,HIS PROFIT AS A PERCENTAGE OF HIS COST PRICE HnPERCENTAGE PROFIT = ((SELL - COST) / COST) * 100 % WHERE SELL = SELLING PRICE, COST = COST PRICEaA14L 14 PERCENTMAS ((48 - 42) / 42) X 100N= 144hS}IB= 149